* @returns {number[]} nums1每个元素在nums2中对应的「下一个更大元素」,无则返回-1
writev(batch) { for (const c of batch) addChunk(c); },,这一点在Line官方版本下载中也有详细论述
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they are the same1 slice, and mutating one will mutate the other.,更多细节参见51吃瓜
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char bucket = h->bucket;